CivilAxisCivilAxis
☕ Support🌐 Community
Tiếng Việt

Moment of Inertia, Section Modulus & Polar Moment - Theory

The theory behind this calculator: what the area moment of inertia (I), elastic section modulus (W), polar moment of inertia (Iₚ) and radius of gyration (i) mean, how the centroid and parallel-axis theorem are used, and the standard closed-form formulas for the common cross-section shapes.

📐Open the interactive moment of inertia calculator

What is the moment of inertia of a section?

The area moment of inertia (also called the second moment of area) is a geometric property of a cross-section that quantifies how its area is distributed about an axis. It governs how stiff and how strong a beam or column is in bending: the further the material lies from the bending axis, the larger the moment of inertia and the more bending the section resists. It has units of length to the fourth power (mm⁴, cm⁴, in⁴). For an elemental area dA at distance z from the axis,

Iy=z2dA,Iz=y2dAI_y = \int z^{2} \, dA, \qquad I_z = \int y^{2} \, dA
yzCc
Centroid C, major axis y-y, minor axis z-z, extreme-fibre distance c

Properties are always reported about the centroidal axes - the axes through the area\'s centre of mass. Following Eurocode 3 (EN 1993) the major (strong) axis is labelled y-yy\text{-}y and the minor (weak) axis z-zz\text{-}z. Bending about the major axis produces the smallest deflection for a given load.

Section modulus and bending stress

The elastic section modulus WW turns the moment of inertia into a strength measure. It is the moment of inertia divided by the distance cc from the centroid to the extreme fibre:

W=Ic,σ=MW=McIW = \dfrac{I}{c}, \qquad \sigma = \dfrac{M}{W} = \dfrac{M\,c}{I}

The bending stress σ\sigma is largest at the fibre furthest from the centroid. For an asymmetric section (a tee, a channel) the top and bottom fibres are at different distances, so the section has a different modulus - and a different peak stress - top and bottom. The calculator reports the modulus for all four extreme fibres.

Polar moment of inertia

The polar second moment of area IpI_p measures resistance to twisting about the longitudinal axis. By the perpendicular-axis theorem it is simply the sum of the two in-plane values:

Ip=Iy+IzI_p = I_y + I_z

For a solid circle this gives Ip=πd4/32I_p = \pi d^{4}/32. Note that for non-circular sections the true St. Venant torsion constant JJ (which appears in the torsional stiffness GJGJ) is not equal toIp\,I_p; the polar second moment of area reported here is exact only for circular sections.

Radius of gyration

The radius of gyration is the distance from the axis at which the whole area could be concentrated to give the same moment of inertia. It is central to column buckling - the slenderness is the buckling length over the radius of gyration, and buckling occurs about the weaker axis (smaller ii).

iy=IyA,iz=IzAi_y = \sqrt{\dfrac{I_y}{A}}, \qquad i_z = \sqrt{\dfrac{I_z}{A}}

The parallel-axis theorem

Built-up sections (I-sections, channels, tees) are split into simple rectangles. Each rectangle\'s moment of inertia is first found about its own centroid, then transferred to the overall section centroid with the parallel-axis theorem:

I=Ic+Ad2I = I_c + A\,d^{2}
ref. axisCd
I = I_c + A·d² - area shifted distance d from the reference axis

where IcI_c is the moment of inertia about the part\'s own centroid, AA its area andd\,d the distance between the two parallel axes. Summing the shifted contributions of every part gives the section\'s moment of inertia. The same procedure locates the centroid first, as the area-weighted average of the part centroids.

Standard formulas

For the common solid shapes the closed-form formulas (about the major centroidal axis) are:

ShapeArea AMoment of inertia ISection modulus W
Rectangle (b × h)bhb\,hbh312\dfrac{b\,h^{3}}{12}bh26\dfrac{b\,h^{2}}{6}
Solid circle (d)πd24\dfrac{\pi d^{2}}{4}πd464\dfrac{\pi d^{4}}{64}πd332\dfrac{\pi d^{3}}{32}
Hollow circle (d, dᵢ)π(d2di2)4\dfrac{\pi (d^{2}-d_i^{2})}{4}π(d4di4)64\dfrac{\pi (d^{4}-d_i^{4})}{64}π(d4di4)32d\dfrac{\pi (d^{4}-d_i^{4})}{32\,d}
I / wide-flange (b, h, tf, tw)2btf+twhw2\,b\,t_f + t_w h_wbh3(btw)hw312\dfrac{b\,h^{3}-(b-t_w)h_w^{3}}{12}2Ih\dfrac{2I}{h}
T-section (b, h, tf, tw)btf+twhwb\,t_f + t_w h_w(Ic,i+Aidi2)\textstyle\sum (I_{c,i}+A_i d_i^{2})Icb\dfrac{I}{c_b}
Triangle (b × h)bh2\dfrac{b\,h}{2}bh336\dfrac{b\,h^{3}}{36}bh224\dfrac{b\,h^{2}}{24}

I-section (wide-flange beam)

The I-section is the workhorse of steel construction. Because it is doubly symmetric, its centroid is at mid-height and the simplest way to find the major-axis moment of inertia is the "full rectangle minus the two side voids"method: take the solid b×hb \times h rectangle and subtract the two rectangular gaps either side of the web, each (btw)/2(b-t_w)/2 wide and hw=h2tfh_w = h - 2t_f tall:

Iy=bh3(btw)hw312,Iz=2tfb3+hwtw312I_y = \dfrac{b\,h^{3} - (b - t_w)\,h_w^{3}}{12}, \qquad I_z = \dfrac{2\,t_f\,b^{3} + h_w\,t_w^{3}}{12}

The minor-axis value IzI_z is dominated by the two flanges (their b3b^{3} term). The section moduli follow as Wy=2Iy/hW_y = 2I_y/h and Wz=2Iz/bW_z = 2I_z/b. A real rolled section also has root radii (fillets) at the web–flange junctions; the calculator adds that material when you enter a non-zero radius rr, which slightly increases the area and inertia.

T-section

A tee is singly symmetric, so - unlike the I-section - its centroid is not at mid-height: it sits closer to the flange. You must locate the centroid first as the area-weighted average of the flange and stem, then apply the parallel-axis theorem to each part:

zˉ=Afzf+AwzwAf+Aw,Iy=(Ic,i+Aidi2)\bar{z} = \dfrac{A_f z_f + A_w z_w}{A_f + A_w}, \qquad I_y = \sum \left( I_{c,i} + A_i\,d_i^{2} \right)

Because the centroid is off-centre, the top and bottom fibres are at different distances, so the tee has twodifferent section moduli - Wy,top=Iy/ctW_{y,top} = I_y/c_t and Wy,bot=Iy/cbW_{y,bot} = I_y/c_b - and bends with different peak stress top and bottom. The calculator reports both.

Enter your dimensions in the tool to see every property - area, centroid, IyI_y, IzI_z,Ip\,I_p, the section moduli, the radii of gyration and the plastic modulus - with a live diagram.

Frequently asked questions

The area moment of inertia (second moment of area) measures how a cross-section's area is distributed about an axis. For a rectangle of width b and height h, the moment of inertia about the horizontal centroidal axis is I = b·h³/12. For a solid circle of diameter d it is I = π·d⁴/64. For built-up shapes (I-sections, channels, tees) the section is split into rectangles and each part is summed using the parallel-axis theorem about the overall centroid. This calculator does all of that automatically and reports I about both principal axes.

The moment of inertia I (units mm⁴) describes the stiffness of a section in bending - it appears in deflection and curvature. The elastic section modulus W = I / c (units mm³), where c is the distance from the centroid to the extreme fibre, describes strength: the bending stress is σ = M / W, so for a given moment the largest stress occurs at the fibre with the smallest W. A section can have a large I but a small W if the material is far from one face. This tool reports both, for the top, bottom, left and right fibres.

The polar (second) moment of area Iₚ measures resistance to twisting about the longitudinal axis. By the perpendicular-axis theorem it equals the sum of the two in-plane moments of inertia: Iₚ = I_y + I_z. For a solid circle this gives Iₚ = π·d⁴/32. Note that for non-circular sections the true torsion constant J (used in the torsion-stiffness GJ) differs from Iₚ; this tool reports the polar second moment of area Iₚ = I_y + I_z, which is exact for circular sections.

The radius of gyration i = √(I / A) is the distance from the axis at which the whole area could be concentrated to give the same moment of inertia. It is used in column buckling: the slenderness ratio is the effective length divided by the radius of gyration (L / i), and buckling occurs about the axis with the smaller radius of gyration. This calculator reports i about both axes.

The parallel-axis theorem lets you find the moment of inertia of an area about any axis parallel to its centroidal axis: I = I_c + A·d², where I_c is the moment of inertia about the area's own centroid, A is the area and d is the distance between the two axes. It is essential for built-up sections - each rectangle is computed about its own centroid, then shifted to the overall section centroid before summing.

The major (strong) axis is the one about which the moment of inertia is largest - bending about it deflects the section least. Following EN 1993 (Eurocode 3) the major axis is labelled y-y and the minor (weak) axis z-z. For a typical I-section bent about y-y (the deep direction) I_y is much larger than I_z, which is why beams are oriented with the web vertical. This tool labels results y-y (major) and z-z (minor).

Ready to compute? Get the area, centroid, moment of inertia, section modulus, polar moment and radius of gyration for your own cross-section, with a live diagram.

📐Open the interactive moment of inertia calculator
Rate this
No ratings yet
Sign in to join the discussion.
Loading…