Strut-and-Tie Model Calculator

Design a concrete deep beam using the strut-and-tie method of EN 1992-1-1 §6.5. The calculator builds the strut-and-tie truss for a simply-supported deep beam under a central load - the inclined compression struts, the bottom tension tie and the nodes - then verifies the strut design stress (§6.5.2), the required tie reinforcement (§6.5.3) and the node pressures (§6.5.4, CCC/CCT), each with its utilisation and a clear PASS/FAIL. More D-region templates (corbel, pile cap) are being added.

Free online calculator with step-by-step working and one-click Excel (.xlsx) and PDF export.

Using this strut-and-tie calculator

What it solves

Strut-and-tie modelling is how EN 1992-1-1 §6.5 handles the parts of a concrete structure where ordinary beam theory does not apply - regions where plane sections do not remain plane. That covers deep beams, corbels, pile caps, walls with openings and the zone immediately around a concentrated load or support.

This calculator builds the truss model for a deep beam, resolves the strut and tie forces from the geometry, and checks the compression struts, the nodes and the tension tie against the code limits. It reports the governing check and the strut angle, and warns when the geometry falls outside the range where the model is valid.

Worked example - 3.0 m deep beam carrying 2000 kN

The tool defaults: a 3000 mm span by 2000 mm deep beam, 400 mm wide, 400 mm bearing, carrying a 2000 kN central point load in C30/37 with 500 MPa reinforcement. Span-to-depth is 1.5, comfortably in deep beam territory. These figures come from calling the engine directly, so they are what the tool shows on load.

Support reaction R_A
1000 kN
Internal lever arm z (auto)
1400 mm
Strut inclination theta
43.03 degrees
cot theta
1.071
Strut force
1465.6 kN
Tie force
1071.4 kN
Design concrete strength f_cd
17.0 N/mm2
Strength reduction factor nu
0.88
Strut check
8.74 / 8.98 N/mm2, utilisation 0.974
Node check
6.25 / 12.72 N/mm2, utilisation 0.492
Tie check
1071.4 / 1071.4 kN, utilisation 1.000 - GOVERNS

The tie governs at exactly 1.000 because the tool sizes the reinforcement to match the tie force - that is the design outcome, not a coincidence. What matters is the margin on the other two: the strut is at 0.974, almost fully utilised, while the node has plenty of room at 0.492.

A strut utilisation that close to 1.0 is the number to watch. If the load increased even slightly, the concrete strut - not the reinforcement - would be the limit, and adding more steel would not help. Widening the beam or increasing the bearing length is what relieves a strut.

The strut angle is the design decision

Everything follows from theta. A shallower strut gives a longer lever arm and a smaller tie force, but the strut itself carries more load and the node stresses rise; a steeper strut does the opposite. EN 1992-1-1 constrains the angle to a usable range precisely because the extremes are unserviceable, and the tool flags a model outside it rather than returning a number that looks fine.

At 43 degrees the example sits near the middle of the permitted band, which is where a well-proportioned deep beam usually lands. If your model is being pushed to an extreme angle to make a check pass, the truss layout is probably wrong rather than the section being inadequate.

Formula reference

Design concrete strength
fcd=αccfckγCf_{cd} = \dfrac{\alpha_{cc}\,f_{ck}}{\gamma_C}
Strut strength, cracked
σRd,max=0.6νfcd\sigma_{Rd,\max} = 0.6\,\nu'\,f_{cd}
Strength reduction factor
ν=1fck250\nu' = 1 - \dfrac{f_{ck}}{250}
CCC node (compression only)
σRd,max=k1νfcd\sigma_{Rd,\max} = k_1\,\nu'\,f_{cd}
CCT node (one tie anchored)
σRd,max=k2νfcd\sigma_{Rd,\max} = k_2\,\nu'\,f_{cd}
Tie reinforcement
As=FtiefydA_s = \dfrac{F_{tie}}{f_{yd}}
Design steel strength
fyd=fykγSf_{yd} = \dfrac{f_{yk}}{\gamma_S}
Strut force from geometry
Fstrut=RsinθF_{strut} = \dfrac{R}{\sin\theta}

Assumptions and limits

A strut-and-tie model is a lower-bound plasticity solution: any statically admissible truss that satisfies equilibrium and the stress limits is safe, but different valid trusses give different amounts of reinforcement. The model here is the standard single-strut deep beam layout, which is appropriate for a symmetric point load. A different load arrangement, multiple loads, or an opening in the web needs a different truss that this tool does not build for you.

Because the method is lower bound, it guarantees strength but says nothing about serviceability. Crack width and deflection are not checked here, and a deep beam with a heavily utilised strut can still be unserviceable. Detailing matters as much as the numbers: the tie must be fully anchored past the node, which usually means bends or bearing plates rather than a straight bar stopped at the support.

Distributed reinforcement to control cracking in the web is required in addition to the main tie, and the tool does not size it. Fatigue, fire and seismic detailing are outside the scope.

FAQ

Whenever plane sections no longer remain plane - a span-to-depth ratio below about 3, or the disturbed region within a depth of a concentrated load, a support, a corbel or an opening. The example above is at 1.5, firmly in that territory.

No - the tool sizes the reinforcement to the tie force, so 1.000 is the design result rather than a failure. The numbers worth watching are the strut and node utilisations, which show how much margin the concrete has.

No. The strut is concrete in compression, so more steel does nothing. Increase the beam width, lengthen the bearing, or raise the concrete grade. This is the most common misdiagnosis in strut-and-tie design.

It follows from the geometry once you fix the lever arm, and the tool derives it automatically. A shallower angle reduces the tie force but increases the strut force. Staying within the code range matters - if you are forcing an extreme angle to pass a check, the truss layout is likely wrong.

A CCC node has only compression meeting at it; a CCT node has one tie anchored into it. CCT nodes have a lower permitted stress because the anchored bar disturbs the concrete, and the tool applies the right limit for the node type.

No. Strut-and-tie is a strength method - a lower-bound plasticity solution. Serviceability is a separate check, and web crack-control reinforcement is required in addition to the main tie regardless of what the strength check says.

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